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Beam analysis Help

  1. Aug 27, 2010 #1
    Beam analysis Help!!!

    I have attached the question and my attempt at a solution, although I am pretty sure I have calculated the reactions wrong and therefore my sfd and bmd are wrong as well. Any help to solve this would be great.
    Thanks.
     

    Attached Files:

  2. jcsd
  3. Aug 27, 2010 #2

    PhanthomJay

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    Re: Beam analysis Help!!!

    At quick glance, you have a lot of errors, including signage errors, and incorrect equations. When you sum moments, the 20 kN-m couple must be included..you seem to have crossed it out. When you sum forces in the vertical direction, don't include moments or couples. Watch your plus and minus signs...V_A is 5 kN down. Correct typo errors. Calculate the proper moment for a distributed load. You are on the right track.....keep on pluggin'...
     
  4. Aug 28, 2010 #3
    Re: Beam analysis Help!!!

    Hi.
    I have redone my first equation and got:
    BMc=4(Va)+20=0, therefore Va=5 kn acting upwards
    Then for my second equation I have:
    BMe=-8(5)+20+15(4)-2(Vd)=0, therefore Vd=20kN acting upwards
    Then the sum of the vertical forces:
    5+20-15-15(4)+Vf=0, therefore Vf=50kN acting upwards
    Sum of the moment about F +clockwise:
    Mf-15(4)(2)+10(6)-15(8)+20+5(12)=0, therefore Mf=20kNm

    Thanks for your help. I have redone the equations but I am sure that there is still something wrong as my vertical forces dont sum to give zero.
     
  5. Aug 28, 2010 #4

    PhanthomJay

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    Re: Beam analysis Help!!!

    When you sum moments about C = 0, sum of clockwise moments must equal sum of counterclockwise moments. Since the 20 kN-m couple is clockwise, then Va must be 5 kN downwards to produce the counterclockwise moment of 20 kN-m.
    Again, you are getting careless with signs. If you consider ccw moments as plus, the cw moments must be minus. Correct the first term signage due to your initial error in calculating the direction of Va, then check that sign again for the couple.
    This equation will be OK once you make the necessary numerical value and signage corrections
    Again, make the necessary numerical corrections...I think you will have a good handle on the signage on this one......
    your free body diagrams are good....just watch your signage........sum of clockwise moments = sum of counterclockwise moments..
     
  6. Aug 28, 2010 #5
    Re: Beam analysis Help!!!

    Hi. Does this look any better??
    BMe would be 8(5)-20+15(4)-2(Vd)=0 therefore Vd=40
    Sum of vertical forces:
    5+40-15-15(4)+VF=0 therefore Vf=30
    Sum of moment about F + clockwise: Mf-15(4)(2)+40(6)-15(8)-5(12)=0, therfore Mf=60kNm

    I am also having trouble drawing the shear force and bending moment diagrams for this.
    If possible would you also be able to look at my posts about macaulays method and moment area method ? If you could that would be great, Thanks for your help so far.
     
  7. Aug 29, 2010 #6

    PhanthomJay

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    Re: Beam analysis Help!!!

    , upwards, looks good!
    That first term ,5, should be -5; Solve Vf = 40 upwards
    you forgot the 20 kn-m couple...Mf = 40 kn-m clockwise
    Correct the values...your approach on the shear diagram is good. Your M diagram is a little shaky at the end....moments are max or min at points of zero shear... the slope of the M diagram is the shear at that point
    Yow, I haven't used those methods in 40 years. Funny, all this stuff you learn in college is essential to structural engineering..but when you get out into the work force, you start from scratch...using the basics to guide you...but learning from others as you go. Every job has different requirements. I do a lot of catenary design..never even studied that in school ...but you pick it up as you learn, with the basics as your guide. After 10 years or so, you become the expert, and then everyone asks YOU the questions. Good luck.:wink:
     
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