1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Beam Analysis

  1. Aug 27, 2006 #1
    Can anyone draw me a correct Bending moment diagram and shear force diagram for this beam?
    i have drawn the shear force diagram for this case but I do not know how to draw the bending moment disgram for this case because this question involve a constant moment. Normally the rule for bending moment is the value of bending moment at certain point is the area under shear force diagram from the starting point to that certain point. Can this rule applied on this question as well? I felt the bending moment diagram is quite stange if follow this rule for this question. Can anyone help me?
    Thanks.
     

    Attached Files:

  2. jcsd
  3. Aug 28, 2006 #2

    Pyrrhus

    User Avatar
    Homework Helper

    Hello, the only thing a couple or moment does for the bending diagram is create a "discontinuity" (more like a derivative doesn't exist at said point), just like the loads do on the shear diagram. If the moment is clockwise it goes up (adds to the area [method]), and if its counterclockwise it goes down (substract to the area [method]).
     
    Last edited: Aug 28, 2006
  4. Aug 28, 2006 #3
    Does it mean when there is a constant moment at point b, then we should either add or substract that value of constant moment in that point (either draw a straight line goes up or goes down)?
     
  5. Aug 28, 2006 #4

    Pyrrhus

    User Avatar
    Homework Helper

    exactly what i said above.
     
  6. Aug 28, 2006 #5
    One more thing have to be confirmed.
    For uniformly distributed load, Mx = (Ay)(x) - (wx^2)/2 (where x is the distance from staring point to x, Ay is the reaction force at the starting point and w is the force per unit length and Mx is the bending moment)
    Let say if there is a constant moment which is 50N/m at point a ,then Mx become Mx = (Ay)(x) - (wx^2)/2 +50 ??
     
  7. Aug 28, 2006 #6

    Pyrrhus

    User Avatar
    Homework Helper

    Yes +50 if its clockwise.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Beam Analysis
  1. Beam analysis Help (Replies: 5)

  2. Truss Beam Analysis (Replies: 1)

Loading...