1. The problem statement, all variables and given/known data A 10 meter beam with a mass of 100 kg is hinged at the wall with a supporting cable at 6 meters from the hinge, making a 60 degree with the beam. There is a 50 kg person located at 9 meters from the hinge. Assuming equilibrium, what is the tension on the cable, the force on the hinge, and the angle of the reactant force. 2. Relevant equations 1. ΣFx = Rx - TcosΘ = 0 2. ΣFy = Ry + TsinΘ - Fobject - Fbeam = 0 3. TsinΘ(dcable) - Fbeam(dbeam) - Fobject(dobject) *Use 10 m/s2 for the value of gravitational acceleration. 3. The attempt at a solution Alright, so I just wanted to double check to see if I'm actually doing this correctly. First I substitute into the third equation in order to find the cable tension. Tsin60(10 m) - (1000 N)(5 m) - (500 N)(9 m) = 0 T = -3116.68 N My first question is with that bolded segment: is it correct to have it subtracted if I'm looking for T? Should it be added instead since the direction is clockwise? If that's right, then I need to find the force on the hinge, and here is where I really find trouble. ΣFx = Rx - 3116.68cos60 = 0 Rx = 2968.36 N Okay, that part was easy for me, but... ΣFy = Ry + 3116.68sin60 - 1000 - 500 = 0 Ry = 1199.12 I asked my instructor about this, but he insists this is incorrect (which I'm sure it is). He is telling me to use 6F +1000(1) = 500(3) I have only a vague understanding of what is involved in this equation. Could someone help me wrap my head around this a little better?