(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a beam is loaded and supported as shown, determine the reaction at point A

see attachment --> the small circle in the beam is not a hole, it is supposed to represent the point at which the moment is about

2. Relevant equations

torque tau = r*F*sin(theta)

3. The attempt at a solution

i do know there is a torque being applied by the 2kN force, such that torque = (4m)(-2kN)sin(90) = -8kN, assuming the positive is upwards

the moment at 2m is given to be 3kN m

i know i did something wrong, because the reaction at A is +2kN (upward), opposite to the applied load at 4m, and the given moment about A, M_A = 11kN m CCW

i can understand the reasoning behind the reaction at A, but how did they calculate the moment about A?

i tried using a free body diagram, but i feel i am missing something and thus not moving in the correct direction with this problem, did i do the FBD correct? see attachment

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# Homework Help: Beam and loads around a point

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