# Beam with 2 hinges

1. May 4, 2015

### DrVirz

Hi all,

Having trouble with the following question, trying to work out the FBD and forces. I am fine with working out the max tensile and compressive forces however I can't get that far as the two hinges are throwing me off. As I understand, the moment at the hinges should be 0, is this correct? I think my RDy and RAy are incorrect as I somehow have to incorporate vertical forces at C and B..?

I have attached a photo of the question and my attempted solution for the forces.

2. May 4, 2015

### x86

Correct, the hinge applies zero moment. Also there is also a resistive moment being applied by the two wall connections. (But it looks like you included that).

Try to take apart the beam and include internal forces.

Last edited: May 4, 2015
3. May 4, 2015

### DrVirz

This is where I am getting confused. Because the beam has 2 hinges, would I split the beam into 3 parts. Then at each hinge I would have a force in the y direction (and x however this is neglected). So for section 1 at B I would have a positive y force, for section 2 at B I would have a negative y force?

4. May 4, 2015

### x86

Right, whenever you have a hinge there are two unknowns: +y and +x. And you can actually split it into 4 parts. 1) the whole beam, 2) left side, 3) right side, 4) middle

If you're unsure of the direction, just assume its in the positive direction. If you solve it and its negative, you know your direction was wrong.

5. May 4, 2015

### x86

Also just reading your question again: you said something about the moment at the hinges/pins being zero. I took statics a long time ago and I don't know if this is true.

However, I know for a fact the moment applied by the hinge is zero.

If you are told that the body is in equilibrium, then the moment anywhere is zero.

But if you are told nothing, I don't know if we can say the moment at the pin is zero or not.

Perhaps you should check your notes for this.

6. May 5, 2015

### PhanthomJay

A pinned connection cannot support any moment, and neither can there be any moment in the beam at that connection. A pinned support cannot support any moment, but there may or may not be a moment in the beam at that support, depending upon whether the pinned support is located at the end of the beam or in between the ends.
In this problem, no moment at pins, and no moment in beam at those pins. The support reaction forces and moments are correct, and the proper direction (cw vs. ccw) of the fixed support moments are shown in the calcs correctly, but assumed incorrectly in the figure.
Note that the reactions at supports A and D are external to the beam. The forces at B and C are internal, and only show up when taking a free body diagram of the section BC. AB, or CD. They don't show up when looking at the entire beam system.

7. May 5, 2015

### DrVirz

This clears up a lot! Thanks for that. I will go and do the rest of the question when I get home later today.