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Bearing load beam equation

  1. Aug 12, 2013 #1
    1. The problem statement, all variables and given/known data

    Need to know the bearing load for a linear slide i'm working on, two spaced bearings with an extended load off the end of the slide.

    LWYoV2A.jpg

    2. Relevant equations

    What equation do I need to apply? What examples are out there?

    3. The attempt at a solution
     
  2. jcsd
  3. Aug 12, 2013 #2

    SteamKing

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    You need to apply the equations of static equilibrium to determine R1 and R2.
     
  4. Aug 12, 2013 #3
    I'm still not sure how to apply, I can't find any relevant examples. The two distances are 1.5m and 1m, bearing spread and mass extended.
     
  5. Aug 12, 2013 #4
    R1 = 1/2.5*(30*1) = 12kg
    R2 = 1/2.5*((30*2.5)+(30*1)) = 42kg

    This is how I've done it, if anyone can give me some guidance that'd be great.
     
  6. Aug 12, 2013 #5
    Use equilibrium equations

    Lets assume both reactions (R1, R2) are facing upwards.

    Now we do the sum of forces in the Y direction=0, where upwards is positive.

    So, Sum of Fy=0: R1 + R2 - 30=0

    Now lets take the sum of the moments at point 1 equal to zero, where anti-clockwise is positive.

    So, Sum of M1=0: (1.5)(R2) -(2.5)(30)= 0
    (1.5)(R2)=75
    R2= 75/1.5
    R2=50kg

    Substituting in the 1st equation:

    R1 + 50 -30 =0
    R1 +20=0
    R1= -20kg

    So your reactions R1 and R2 are -20kg, 50kg respectively.
     
  7. Aug 13, 2013 #6
    Thanks I understand now, appreciate your help.
     
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