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Beer Mug Angle

  • Thread starter Let It Be
  • Start date
  • #1
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1. A bartender slides a beer mug at 1.50m/s towards a customer at the end of a frictionless bar that is 1.2m tall. the customer makes a grab for the mug and misses, and the mug sails of the end of the bar. What are the speed and direction of the mug at impact?


2. Vx=Vocosθ
Vy=Vosinθ
V=√Vx^2+Vy^2
θ=tan-1(Vy/Vx)


3. The correct answer apparantly is 5.08m/s and θ=-72.8°. I didn't get that...
 

Answers and Replies

  • #2
AlephZero
Science Advisor
Homework Helper
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The equations you give are OK to find the speed and direction, but you need some more equations to find Vx and Vy when the mug hits the floor.
 
  • #3
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The equations you give are OK to find the speed and direction, but you need some more equations to find Vx and Vy when the mug hits the floor.
I don't know how to solve the problem with the equations I do have though...
 
  • #4
25
1
How do you think vx and the sliding velocity compare?

Think about it, don't try use the equations!
 
  • #5
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How do you think vx and the sliding velocity compare?

Think about it, don't try use the equations!
I know I need to find Vf for the speed when the mug hits the floor. And then direction idk
 
  • #6
25
1
Well, start with the x-component of v_f. What will that be?

Remember there's no friction whilst the mug is sliding, and I assume there is no air resistance.
 

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