Solve Car Accident at 32.7m Cliff: Help Needed!

[avenue]

I have a HW problem that says:

A car drives horizontally off the edge of a cliff that is 32.7 m high. The police at the scene of the accident note that the point of impact is 153 m from the base of the cliff. How fast (in terms of km/h) was the car traveling when it drove off the cliff?

I've worked it out like 10 times. I only have one more chance to get it wrong on my online homework.

Someone please help...
jejewitt@yahoo.com

 

[whozum]

How much time did the car have to fall?
If the car is traveling at a constnat speed horizontally and it traveled 153m, how fast was it traveling in that amount of time?

 

[quicknote]

I understand that the situation you are describing is a complex and urgent one. In order to solve this problem, it is important to approach it systematically and with precision.

Firstly, it is important to gather all the necessary information. In this case, we know that the car drove off a cliff that is 32.7 m high and the point of impact is 153 m from the base of the cliff. We also need to know the acceleration due to gravity, which is approximately 9.8 m/s^2.

Next, we can use the kinematic equations of motion to solve for the initial velocity of the car. The equation we will use is:

v^2 = u^2 + 2as

Where v is the final velocity (which we can assume to be 0 as the car has reached the ground), u is the initial velocity, a is the acceleration due to gravity, and s is the displacement (in this case, 153 m).

Substituting the values we know, we get:

0^2 = u^2 + 2(9.8)(153)

Rearranging the equation, we get:

u = √(2as)

Plugging in the values, we get:

u = √(2(9.8)(153))

u = √(3003.6)

u = 54.8 m/s

To convert this to km/h, we multiply by 3.6:

u = 54.8 x 3.6

u = 197.28 km/h

Therefore, the car was traveling at approximately 197.28 km/h when it drove off the cliff.

I understand that this may be a difficult problem, but with the right approach and careful calculations, I am confident that you will be able to solve it correctly. If you are still having trouble, I recommend seeking assistance from a tutor or classmate who may be able to provide additional guidance. Good luck!