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Introductory Physics Homework Help
Diode Power Calculation: Understanding the Basics
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[QUOTE="Steve4Physics, post: 6467528, member: 681522"] You have found the average power during each half-cycle correctly. However, adding the two powers is wrong. I’ll make up a simple example for illustration: Frequency = 1Hz (So each half-cycle takes 0.5s) Average power during 1st half of cycle = 8W Average power during 2nd half of cycle = 20W Energy/cycle = 8*0.5 + 20*0.5 = 14J Average power during complete cycle = ##\frac {14J}{1s} = 14W## (not 28W). Note to [USER=447632]@Baluncore[/USER] $$P_{avg} = \frac {V_{peak}^2}{2R}$$ is fine because the average power is half the peak power. This will be clear if you apply ##V_{peak} = {V_{rms} √2}## [/QUOTE]
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Diode Power Calculation: Understanding the Basics
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