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It's just that it helps to understand what I'm doing.

4. [HRW6 7.PN.04.] The block in Fig. 7-10a lies on a horizontal frictionless surface and is attached to the free end of the spring, with a spring constant of 65 N/m. Initially, the spring is at its relaxed length and the block is stationary at position x = 0. Then an applied force with a constant magnitude of 3.3 N pulls the block in the positive direction of the x axis, stretching the spring until the block stops.

Assume that the stopping point is reached.

Okie doke..

When the block stops, its acceleration is zero. When the acceleration is zero, the net force must be zero. So Fapplied must equal the spring force. The applied force is 3.3, so then I can use Hooke's law

Fspring = -Kx

-3.3 = -65x

3.3/65 = .0507 m

What did I do wrong?

4. [HRW6 7.PN.04.] The block in Fig. 7-10a lies on a horizontal frictionless surface and is attached to the free end of the spring, with a spring constant of 65 N/m. Initially, the spring is at its relaxed length and the block is stationary at position x = 0. Then an applied force with a constant magnitude of 3.3 N pulls the block in the positive direction of the x axis, stretching the spring until the block stops.

Assume that the stopping point is reached.

Okie doke..

When the block stops, its acceleration is zero. When the acceleration is zero, the net force must be zero. So Fapplied must equal the spring force. The applied force is 3.3, so then I can use Hooke's law

Fspring = -Kx

-3.3 = -65x

3.3/65 = .0507 m

What did I do wrong?

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