[tex]y'+\frac{2}{x}y=\frac{y^3}{x^2}[/tex](adsbygoogle = window.adsbygoogle || []).push({});

[tex]u=y^-^2[/tex]

so [tex]y'+(1-3)p(x)u=(1-3)q(x)[/tex]

[tex]y'-2(2x)u=-2y^3/x^2[/tex]

[tex]y'-4x/y^2=-2y^3/x^2[/tex]

integration factor is [tex]e^{{-2x}^2}[/tex]

is this right so far?

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# Homework Help: Bernouill diff eqn.

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