A large tank of water has a hose connected to it. The tank is sealed at the top and has compressed air between the water surface and the top. When the water height h has the value 3.5 m , the absolute pressure p of the compressed air is 4.20 * 10^5 Pa. Assume that the air above the water expands at cosntant temperature, and take the atmospheric pressure to be 1.0 * 10^5 Pa. When the h=3.5 m, velocity = 26.2 m/s. When h=3.0, v=16.1m/s. When h=2.0 m, v = 5.44 m/s. How do I solve for when the velocity equals 0? I realize that I have to rearrange the Bernouilli Equation. Do [(1/2)pv1^2] and [(1/2)pv2^2] cancel when this happens?