1. The problem statement, all variables and given/known data Find the general solution of the following differential equation. y'+4xy=10xy2cos(x2) 2. Relevant equations The usual Bernoulli equation ones: y'+p(x)y = g(x)ya u(x)=[y(x)]1-a u'+(1-a)pu = (1-a)g 3. The attempt at a solution I got up until the general solution part.. I'll just type bits of it out because it'll take me ages (I'm a slow typer). So in the equation, a=2, p(x)=4x, g(x)=10xcos(x2) Change of variables: u(x)=[y(x)]1-a = y-1 and u'+(1-a)pu = (1-a)g => u'-4xu = -10xcos(x2) Now here's where I get confused.. General solution: u= e[tex]\int[/tex]p(x)dx[[tex]\int[/tex]r(x)e[tex]\int[/tex]p(x)dxdx+c where p=-4x, r=-10xcos(x2) u= e[tex]\int[/tex]-2x^2[[tex]\int[/tex](-10xcos(x2)e[tex]\int[/tex]-2x^2)dx+c Argh.. that's messy, I hope it makes sense. Anyway, I can't seem to figure out that integral... I've used parts and stuff but I don't seem to be getting anywhere. Any help would be appreciated.