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Introductory Physics Homework Help
Bernoulli, Gauge pressure in hose?
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[QUOTE="kogai, post: 4512089, member: 488701"] So the left side is P[SUB]0[/SUB] + ρgh + .5ρV[SUB]1[/SUB][SUP]2[/SUP]? Or should it be 2ρgh? How would I set the right side to be able to find the gauge pressure? The only pressure on the outside of the hose is P[SUB]0[/SUB], so wouldn't they just cancel? Or would the left side be P + .5ρV[SUB]1[/SUB][SUP]2[/SUP] since P = P[SUB]0[/SUB] + ρgh then P + .5ρV[SUB]1[/SUB][SUP]2[/SUP] = P[SUB]0[/SUB] + .5V[SUB]2[/SUB][SUP]2[/SUP] and solve for P - P[SUB]0[/SUB]? By the way, you're absolutely correct about V[SUB]nozzle[/SUB] being low, both of the solutions I looked at confused the areas and flipped them the wrong way, the actual speed is 109 m/s, if I didn't mess it up again. I'm skeptical of the http://people.physics.tamu.edu/kattawar/final%20exam%20221%20sp-09.pdf. Would you mind taking a look at it and seeing if it's set up correctly or if I should ignore it completely? [/QUOTE]
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Bernoulli, Gauge pressure in hose?
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