Bernoulli ODE question

  • Thread starter cue928
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I am working on the following Bernoulli ODE: 3xy^2 y' = 3x^4 + y^3. I come up with n = -2, so v = y^3 and y' = (1/3)v^(-2/3) v'. My integrating factor was x^-1. I end up with y^3 = X^2 + Cx yet the book has the same thing except X^4 instead of X^2. That makes me think I'm going wrong with multiplying it through but I don't see where.
 

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tiny-tim
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hi cue928! :smile:

(try using the X2 icon just above the Reply box :wink:)
My integrating factor was x^-1. I end up with y^3 = X^2 + Cx yet the book has the same thing except X^4 instead of X^2.

it should have worked :confused:

show us how you got the x2
 
  • #3
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It was right, I just made a stupid mistake that led me to think it was something bigger than what it really was.
 

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