A small circular hole 6.00 mm in diameter is cut in the side of a large water tank, 14.0 m below the water level in the tank. The top of the tank is open to the air. A) What is the speed of efflux? sqrt(2*g*h) = 16.6 m/s B) What is the volume discharged per unit time. This is the equation i believe, dV/dt = A*v I dont know exactly how to get A.. any Hints?