1. The problem statement, all variables and given/known data A cylindrical water tunnel runs through a dam. The entrance to the tunnel has a radius of 1.30m and is located at a depth of 22.0m below the surface of the water. The other end of teh tunnel has a radius of 0.840m., is 46.0m below the water's surface, and is open to the air. a) What is the speed of the water when it exits the tunnel? b) Determine the absolute pressure of of the water just after it enters the tunnel 2. Relevant equationsv=Sq Rt (2gh) P1 + (1/2 x density x v1 squared) + (density x g x h1) = P2 + (1/2 x density x v2 squared)+ (density x g x h2) 3. The attempt at a solutionI really don't know where to start as we don't know the velocity at the entrance. v= the square root of 2 x 9.81 x (46-22) = square root 470 = 21.6 m\s We can ignore density. But we don't know P1 or P2 so I'm stumped! Please help me understand the question and if I'm using the correct equations.