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Bessel function

  1. Dec 20, 2005 #1
    why does the v parameter in the bessel function
    x^2y``+xy`+(x^2-v^2)y=0 have to be real and nonegative?
  2. jcsd
  3. Dec 20, 2005 #2


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    In the differential equation, there are no constraints on v (other than being finite) and solutions exist. If you want to call the solutions "standard Bessel functions" then the values of v are restricted. Generally, however, Bessel functions can have both complex arguments and indices.
  4. Dec 23, 2005 #3
    thank you very much!
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