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Physics
High Energy, Nuclear, Particle Physics
Beta Decay, why did they have to resort to Neutrinos?
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[QUOTE="malawi_glenn, post: 6862140, member: 71734"] Neutrinos are detecable for sure, because they interact. In either way, you have to assume the existence of a very light mass and very weakly interacting particle. Then you work out what predictions such theory would pose. And as I wrote, it is a standard calculation to derive the energy spectrum of the electron in beta decay - which you can compare with experimental data (excellent agreement). Such spectra would only depend on the mass of the nuclei involved. If you propose "nah there are no neutrinos that is being emitted in beta-decay, the electrons are ejected due to an incomming flux of neutrinos with unknown energy distribution..." - then how are you gonna explain that it is not the other way around? Like what I did in the previous paragraph. Then you would need to have different energy distributions of the incomming neutrino fluxes, depending on what your mother nuclei is. And voila you have an epicycle theory in some sense... [/QUOTE]
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Beta Decay, why did they have to resort to Neutrinos?
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