Non-Relativistic Bethe-Bloch Calculation for Alpha Particle in Xenon"

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In summary, the problem is with the units and the energy loss for alpha particles is plotted on a logarithmic scale to account for the extreme energy loss.
  • #1
CloudNine
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Hi all,

I got an exercise to plot Bethe-Bloch function (ignore the "Compare..." part, it belongs to an exercise above), for alpha particle in Xenon. See the question below:

Capture.PNG


I've been struggling to get a plot that makes sense. I checked my parameters and the units a million times already, but couldn't find where the problem is. On paper, the units I'm left with, after all the conversions, are MeV/cm, which is exactly what I want. But again, I get a weird curve...

Here is the Matlab code I wrote:

Code:
E_dat=[ 0.001    0.002    0.003    0.003    0.004    0.005    0.006    0.007    0.008    0.009    0.010    0.013    0.015    0.018    0.020    0.023    0.025    0.028    0.030    0.035    0.040    0.045    0.050    0.055    0.060    0.065    0.070    0.075    0.080    0.085    0.090    0.095    0.100    0.125    0.150    0.175    0.200    0.225    0.250    0.275    0.300    0.350    0.400    0.450    0.500    0.550    0.600    0.650    0.700    0.750    0.800    0.850    0.900    0.950    1.000    1.250    1.500    1.750    2.000    2.250    2.500    2.750    3.000    3.500    4.000    4.500    5.000    5.500    5.544    6.000    6.500    7.000    7.500    8.000    8.500    9.000    9.500    10.000 ];%MeV

% Constants for Bethe-Bloch equation:
rho = 0.010592; % [g/cm^3] for Xenon in 2 bar and 25 C conditions
qe=1.602e-19; % C
me=9.109e-28; % g
NA=6.0226e23; % Avogadro constant, 1/mol
K=9e13; % K=1/4*pi*epsilon0 , units of N*cm^2/C^2
Z1=2;
malpha=6.646e-24; % g
v=sqrt(2*E_dat/malpha); % sqrt(MeV/g)
A=131.293; % g/mol
Z=54;
I=(16*Z^0.9)/1e6; % MeV
first=-rho*4*pi*NA;
second=((qe^4)*(K^2))/me;
third=((Z1^2)./(v.^2));
fourth=Z/A;
fifth=log((2*me*(v.^2))./I);
aaa=first*second*fourth;
bbb=third.*fifth;
dEdX_BB=aaa*bbb*3.9e21; % 3.9e21 is to convert from N^2*cm/MeV to MeV/cm

plot(E_dat,dEdX_BB)
xlabel('Alpha energy [MeV]')
ylabel('dE/dX [MeV/cm]')
title('Stopping power of non-relativistic analytical expression for alpha particle Xe')

I know that the peak shouldn't be that sharp, narrow, high (10^4!) and not that close to zero. Also, the dE/dx trend should be more moderate and to spread much more nicely, than this sharp drop to 0..
Would appreciate your thoughts!

Thanks.
 
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  • #2
You could include your plot here.
Alpha particles at 1 keV will have an extreme energy loss even in a gas.
 
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  • #3
Use a reasonable set of units! Newtons, cm, eV?
What value is the ionization potential?
 
  • #4
mfb said:
You could include your plot here.
Alpha particles at 1 keV will have an extreme energy loss even in a gas.
Here's the plot:
Capture.PNG


I know it is not the right plot as the lecturer showed something similar in class and it looked differently...
 
  • #5
hutchphd said:
Use a reasonable set of units! Newtons, cm, eV?
What value is the ionization potential?
There are a lot of variables in this formula. I changed all units so I can end up with MeV/cm. I suppose the problem is indeed relevant to the units, but, as I wrote, I can not find the mistake... hence this post.
The ionization potential is given in eV in the exercise so I turned it to MeV.
Would you mind going over the units and see if I messed up? I've reached to a dead-end...
 
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  • #6
There is a good reason the energy loss is usually plotted on a logarithmic scale.
 
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  • #7
mfb said:
There is a good reason the energy loss is usually plotted on a logarithmic scale.
You are right. However, in this case (as I know what to expect), it should look just fine even on a regular scale.
 
  • #8
The curve should look something like - one would have to multiply by atomic density
https://www-nds.iaea.org/stopping/stopping_201410/index.html

Also, not quite as it's alpha particles in air and graphite.
https://www.nist.gov/system/files/documents/2017/04/26/newstar.pdf (see figures A.10 and A.11 respectively), which are somewhat consistent with the plot above.

It would help to plot energy in a log-scale as others suggested.

There should be a peak in S(E) about 0.6 MeV, so something appears to be amiss.

FYI - http://www.srim.org/Citations/Cit 02-54.pdf - but it's not complete.
 

1. What is the Bethe-Bloch equation and how does it relate to alpha particles in xenon?

The Bethe-Bloch equation is a formula used to calculate the energy loss of a charged particle (such as an alpha particle) as it passes through a material (such as xenon). It takes into account factors such as the density of the material, the charge and mass of the particle, and the particle's velocity. It is commonly used in particle physics and radiation therapy to understand and predict the behavior of particles in different materials.

2. Why is the Bethe-Bloch equation considered a non-relativistic calculation?

The Bethe-Bloch equation is considered non-relativistic because it does not take into account the effects of special relativity, which becomes significant at high velocities. For alpha particles, which have relatively low speeds compared to the speed of light, the non-relativistic version of the equation is accurate enough for most practical applications.

3. How is the Bethe-Bloch equation used to calculate the stopping power of xenon for alpha particles?

The Bethe-Bloch equation is used to calculate the stopping power of xenon for alpha particles by plugging in the relevant values for the material and the particle. These values include the density of xenon, the charge and mass of the alpha particle, and the velocity of the particle. The resulting value is the energy loss per unit length (in units of MeV/cm) that the alpha particle experiences as it travels through xenon.

4. What is the significance of the Bethe-Bloch equation in radiation therapy?

The Bethe-Bloch equation is used in radiation therapy to predict the behavior of particles as they pass through different materials in the body. This allows for accurate targeting of tumors and minimizing damage to surrounding healthy tissue. The equation is also used in the design and calibration of radiation therapy equipment.

5. Are there any limitations to using the Bethe-Bloch equation for alpha particles in xenon?

While the Bethe-Bloch equation is a useful tool for understanding the behavior of alpha particles in xenon, it does have some limitations. For example, it does not take into account the effects of multiple scattering, which can be significant for low energy particles. Additionally, it assumes a uniform and continuous medium, which may not always be the case in real-world scenarios.

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