An object is located 36 cm to the left of a biconvex lens of index of refraction 1.5 The left surface of the lens has a radius of curvature of 20 cm. The right surface of the lens is to be shaped so that a real image will be formed 72 cm to the right of the lens. What is the required radius of curvature of the second surface?(adsbygoogle = window.adsbygoogle || []).push({});

Need some clarification on how to approach this. We have that 1.5 = C/v and thus can figure out the speed the light will travel at off the lens. Is the image gonna reflect off the left side then the right, like its two lens? If so I will need to use 1/f=1/d0 + 1/di. Any help is appreciated

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# Homework Help: Biconvex Lens

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