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## Homework Statement

A 14kg bicycle is on a 12 degree incline. A tension scale is connected by a rope to both the rear wheel circumference and a metal bar that is extending the bicycle frame rearward. The line of the rope is at a 30 degree angle to the metal bar. What will be the reading on the tension scale?

## Homework Equations

T = rF

Fslope= m*g*sin(angle)

x component of F = cos(angle) * mag F

## The Attempt at a Solution

I am basing this solution on my solution for Bicycle and Pulley, part 1,

https://www.physicsforums.com/showthread.php?t=148577

but I didn't get any feedback to know whether part 1 was correct. Also I am a little more hazy on part 2, but I want to know if I am right so I'll proceed.

F1 is the force pulling the bicycle down the incline

F1 = m*g*sin(12) = 14kg * sin(12) = 2.96kg

There are 2 forces opposing F1 :

F2, the friction force of the wheel on the incline

F3, the force from the rope

Both forces act on the rear wheel

Considering the direction of the forces acting on the bicycle,

F2 + F3 = F1

F2 = cos(30)* F3 = .866*F3

(Should that be the magnitudes of the forces?)

F1 = 2.96kg

F2 = 1.3

F3= 1.6

So, the tension scale should read 1.6kg

Note: The tension scale on the bicycle of part 1 read 2.96. This means, in part 2, there will be less tension on the rope than in part 1