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## Homework Statement

Coasting along at 7.10 m/s, a 60.0 kg bicyclist on a 7.60 kg bicycle encounters a small hill. If the speed of the bicyclist is 6.00 m/s at the top of the hill, how much work was done on the bicyclist and her bike?

## Homework Equations

KEf-KEi=W

.5mvi^2-.5mvf^2

kg*m^2*s^-2

m=60kg+7.60kg

v=m/s

## The Attempt at a Solution

I tried finding the loss in KE and having that be the work done. I get

.5mVf^2 -.5mVi^2

.5*67.6kg*36 - .5*67.6kg*50.41

I get -487 J and it tells me this is the wrong answer? What did I do wrong?

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