Angular Acceleration of a Cyclist's Wheels: 54 Rev in 10.0 s

In summary, a cyclist with a bike of 36.0 cm radius starts from rest and pedals with constant angular acceleration. After 10.0 s, the wheels have made 54 rev. Using the formula w=w_o+at, where w_o=0, the angular acceleration of the wheels can be calculated. Additionally, since the wheel rolls without slipping, the distance the cyclist has traveled can also be calculated from the formula w = 2πF. It is recommended to refer to the textbook for a better understanding of the basics before posting direct questions based on formulae.
  • #1
melissa_y
17
0
A cyclist starts from rest and pedals such that the wheels of his bike have a constant angular acceleration. After 10.0 s, the wheels have made 54 rev. What is the angular acceleration of the wheels? Use units of "rad/s\^{}2".

If the radius of the wheel is 36.0 cm, and the wheel rolls without slipping, how far has the cyclist traveled in 10.0 s?
 
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  • #2
Melissa, I'm not being rude, but if you want help then you're going to have to post your thoughts on how to answer the questions you've been set. People here will be more than willing to help you out if you show us your working, and explain where you've got stuck. Copying out nine homework questions and expecting people to answer them for you isn't the way things work here.

Tell us your thoughts (as well as the questions!) and if you're genuinely stuck (rather than lazy) then you'll get all the help you need. For more information, read the post which says "read this before posting".

https://www.physicsforums.com/showthread.php?t=4825
 
Last edited:
  • #3
1) [itex]w=w_o + at[/itex]

where [itex]w_o[/itex] = 0

The wheel has made 54 rev in 10 seconds , that means wheel rotates with w= 2 pie F
Calculate w from here and put it in above expressions.


You should first refer to your textbook with thorough reading of the basics before posting direct questions based on formulae.
 

1. What is angular acceleration?

Angular acceleration is the rate of change of angular velocity over time. It is a measure of how quickly the rotational speed of an object is changing.

2. How is angular acceleration related to a cyclist's wheels?

Angular acceleration is directly related to the motion of a cyclist's wheels. As the cyclist pedals and the wheels rotate, there is a change in angular velocity, resulting in angular acceleration.

3. What do the numbers 54 Rev and 10.0 s represent?

The number 54 Rev represents the number of revolutions the cyclist's wheels make in a given time. The number 10.0 s represents the amount of time it takes for the wheels to make those 54 revolutions.

4. How can we calculate the angular acceleration of the cyclist's wheels?

The formula for calculating angular acceleration is angular acceleration = change in angular velocity / change in time. In this case, we can calculate the change in angular velocity by dividing the number of revolutions (54 Rev) by the time (10.0 s). This will give us the angular acceleration in revolutions per second squared (Rev/s^2).

5. Why is angular acceleration important in cycling?

Angular acceleration is important in cycling because it affects the speed and stability of the cyclist's ride. Higher angular acceleration can result in faster speeds while lower angular acceleration can result in slower speeds. It is also important for maintaining balance and control while cycling.

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