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Big Oh notation help?

  1. Aug 5, 2009 #1
    Can someone please explain what it means to say something like
    x = x_0 + \mathcal{O}(y)
  2. jcsd
  3. Aug 5, 2009 #2


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    You must include in your expression a "as x goes to.."

    Without that, it is meaningless.
  4. Aug 5, 2009 #3
    [itex]\cos x = 1 + O(x^2)[/itex] as [itex]x \to 0[/itex] means:
    [tex]\frac{\cos x - 1}{x^2}[/tex]
    is bounded in some neighborhood of [itex]0[/itex] .
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