- #1

Punchlinegirl

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The rod is of negligble mass. The wheel is turning rapidly such that it has an angular momentum of 10.8 kgm^2/s. At what angular speed does the wheel revolve horizontally about the pivot?

I used the equation

L= Iw, substituting .5MR^2 for I

L= .5MR^2 w

10.8=.5(1.36)(.530)^2 w

Solving for w gives 56.5 rad/s which isn't right

Can anyone tell me what I did wrong?