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Bilinear limit

  1. Apr 30, 2012 #1
    { lim (h,k) -> (0,0) } |B(h,k)| / |(h,k)| = 0 for an arbitrary bilinear function. But why? It seems obvious if B = 0 but this is true for ANY bilinear. I'm trying to figure this out so that I can see the definition a general derivative better.
     
  2. jcsd
  3. Apr 30, 2012 #2

    HallsofIvy

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    What does |(h,k)| mean?
     
  4. Apr 30, 2012 #3
    Presumably, |(h,k)| is the norm of the bilinear argument..... which without a bilinear acting upon it is perhaps the norm of the inner product (dot product)?
     
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