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Bimetallic Strip

  1. May 2, 2009 #1
    1. The problem statement, all variables and given/known data
    the bimetallic strip has a thickness x and is straight at temp T.
    What is the radius of curvature of the strip, R, when it is heated to temp T+dT
    Coeff. of linear expansion: a1, a2.
    Assume each each metal has a thickness of x/2 and X<<R


    2. Relevant equations
    L1=L0(1+a1 dT)
    L2=L0(1+a2 dT)
    3. The attempt at a solution
    I was givin the hint that:
    L2=(R+x/4)theta
    L1=(R-x/4)theta
    Where on earth do this +-x/4 come from?!
     
  2. jcsd
  3. May 2, 2009 #2

    Doc Al

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    Staff: Mentor

    If R is the radius corresponding to the center of the strip, then R ± x/4 describes the radius at the center of each metal.
     
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