A 5.62-g sample containing only Mn2(SO4)3(s) and Al2(SO4)3(s) is dissolved in aqueous solution. The metal ions are precipitated as hydroxides, which are pyrolyzed in air to produce 2.06 g of a mixture of Mn2O3(s) and Al2O3(s). What was the percent Mn in the original sample? what i did so far: found molar mass of Mn2O3 and Al2O3 157.873g/mol and 101.961 g/mol respectively total 259.834g/mol Mn2O3 takes up 60.76% of the total molar mass and Al2O3 takes up 39.24%. so does that mean 60.76% of the 2.06 g mixture would be Mn2O3 and 39.24% would be from Al2O3? Then i don't know what to do next help?