Homework Help: Binary Search tree

1. Aug 10, 2014

Maylis

1. The problem statement, all variables and given/known data
Binary search trees

In these problems you will set up a binary search tree and write some associated functions that make
the search tree useful.

Students in the workspace. Students contains a list of student names and corresponding ID
numbers. In this first task, you will write a function to insert a student's name and ID number
into a binary search tree keyed to the ID numbers. Your function will have the declaration line

Code (Text):
function newTree = bstInsert(bst, rootInd, name, idNumber)
The inputs are
1. bst: a structure array with fieldnames
$\bullet$ name
$\bullet$ ID
$\bullet$ left
$\bullet$ right
(very similar to what was described in the lecture videos) representing the binary search tree.
You may assume that the struct array is not empty and that the root of the binary search
tree is the first element of the array.
2. rootInd: the current root index
3. name: the name to be inserted into the search tree
4. idNum: the ID number to be inserted into the search tree

Remember that a new element with the name and ID number to be inserted must be appended
to the struct array bst before any elements of bst can be modi ed to point to its index.

The most natural way to write this function is with a recursive implementation that simply com-
pares the ID number to a current node, and based on the result of that comparison calls itself
recursively on the left or right subtree of the current node.

Note: For this problem, use the convention that if a key to be inserted is equal to an existing
key, the key to be inserted will be placed in the left subtree of the existing key.
The following code is useful for testing bstInsert. It initializes a binary search tree with the rst
row of the cell array Students and uses bstInsert to place the remainder of the student names
and ID numbers in the search tree.
Code (Text):
studentTree = struct('name',Students{1,1},...
'ID',Students{1,2},...
'left',0,...
'right',0);

for k = 2:size(Students,1)
studentTree = bstInsert(studentTree,1,Students{k,1},Students{k,2});
end
It may also be useful to modify the function bstinorder that was made available along with the
lecture videos to view the elements of the binary search tree you create.

2. Relevant equations

3. The attempt at a solution
This is the given code for bstinorder
Code (Text):
function bstinorder(tree,index)
% Print the part of a tree under index using inorder traversal
% Input the tree and the index
% Assumes the fields are 'key', 'left' and 'right'

% descend the left subtree
if tree(index).left ~=0
bstinorder(tree,tree(index).left)
end

% print current key when there is none smaller
disp(tree(index).key);

% descend the right subtree
if tree(index).right ~=0
bstinorder(tree,tree(index).right)
end
The studentTree structure array only contains one student

Code (Text):
studentTree =

name: 'Jim'
ID: 19907875
left: 0
right: 0
Here is my modification.
Code (Text):
function newTree = bstInsert(bst, rootInd, name, idNumber)
% Print the part of a tree under index using inorder traversal
% Input the tree and the index
% Assumes the fields are 'key', 'left' and 'right'

% descend the left subtree
if bst(rootInd).left ~= 0
newTree = bstInsert(bst,bst(rootInd).left,bst(rootInd).name,bst(rootInd).idNumber);
end

% print current key when there is none smaller
disp(bst(rootInd).name);

% descend the right subtree
if bst(rootInd).right ~= 0
newTree = bstInsert(bst,bst(rootInd).left,bst(rootInd).name,bst(rootInd).idNumber);
end
I know since Jim has a value of left and right of 0, he must be a leaf node. His student ID also is the largest one, so I know he most be the bottom right leaf nodes in the binary tree. However, I don't know how to append the next student to be his parent. I run this and get the following error

Code (Text):
Error in bstInsert (line 7)
if bst(rootInd).left ~=0

Output argument "newTree" (and maybe others) not assigned
during call to
"C:\Users\Owner\Documents\MATLAB\bstInsert.m>bstInsert".

2. Aug 11, 2014

.Scott

As written, your function will not assign a value to newTree unless either the left or right branch are zero.
There must be more to bstInsert that you are not showing us.

Also, the last two argument of bstInsert are not used in the code you show.

You're also not telling us whether any of your disp's are being executed.

3. Aug 11, 2014

Maylis

I copy pasted the entire code I wrote for bstInsert. I modified it to at least include all input arguments
Code (Text):
function newTree = bstInsert(bst, rootInd, name, idNumber)
% Print the part of a tree under index using inorder traversal
% Input the tree and the index
% Assumes the fields are 'key', 'left' and 'right'

% descend the left subtree
if bst(rootInd).left ~= 0 && bst(rootInd).ID > idNumber && strcmpi(bst(rootInd).name,name)
newTree = bstInsert(bst,bst(rootInd).left,bst(rootInd).name,bst(rootInd).idNumber);
end

% print current key when there is none smaller
disp(bst(rootInd).name);

% descend the right subtree
if bst(rootInd).right ~= 0 && bst(rootID).ID < idNumber && strcmpi(bst(rootInd).name,name)
newTree = bstInsert(bst,bst(rootInd).left,bst(rootInd).name,bst(rootInd).idNumber);
end
The first student, Jim, does display

Code (Text):
Jim
Error in bstInsert (line 7)
if bst(rootInd).left ~= 0 && bst(rootInd).ID > idNumber

Output argument "newTree" (and maybe others) not
assigned during call to
"C:\Users\Owner\Documents\MATLAB\bstInsert.m>bstInsert".

Last edited: Aug 11, 2014
4. Aug 11, 2014

.Scott

If that's all of bstInsert, then the error message makes sense.
What do you want to do when both left and right are zero? As it stands now, you print bst(rootInd).name ("Jim") and then return from bstInsert with no value to assign to newTree (hence the "not assigned" error).

So what should you do when both left and right are 0?

Last edited: Aug 11, 2014
5. Aug 11, 2014

Maylis

I got help from a grad student for my class, so the problem has been solved now.

6. Aug 11, 2014