It seems that for the case of the Electron in the Ground State of the Hydrogen Atom that when the value of the Binding Energy (13.6 eV), as calculated by Bohr, is divided by the separation distance (the Bohr Radius = 5.29 x 10^-11 m) we only get half of the Coulomb Force (4.11 x 10^-8 N) which exists between the Proton and the Electron (8.22 x 10^-8 N). Am I missing a factor of 2 when dividing the Binding Energy by the radius? Is there a relationship between the value of the Binding Energy of the Deuteron (2.22 MeV) and the actual value of the Force that exists between the Proton and the Neutron at a distance of approximately 2.13 x 10^-15 m ? What is an approximate value of this Force between the Nucleons(in Newtons)? Thanks.