# Binding Energy question

1. Nov 14, 2004

### stunner5000pt

Protonium consists of Proton and an antiproton in a bound state

first of all waht is a bound state - is it a proton orbiting an antiproton or vice versa??

a) what is teh Binding energy of protonium?
do i use this formula??

$$E = \frac{ \mu e^4}{8 \epsilon_{0}^2 h^2}$$

b) How far apart are the antiproton and proton in this ground state??

$$r = \frac{\epsilon_{0} h^2}{\mu \pi Z e^2} n^2$$

where $$\mu = \frac{m_{p}^2}{2m_{p}} = \frac{m_{p}}{2}$$

c) What is teh angular momentum of the proton or antiproton in the 3rd excited state?

so the 3rd excited state is n = 4

$$L = \mu v r = n \frac{h}{2 \pi}$$

and i find v using the formula given??

andi right so far if you could correct me on any of these please please tell me!

also i coul also use your help for this thread too, similar topic question!