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## Homework Statement

I am trying to figure out if I have a 20% chance to get what I want (let it = x) and I have 6 chances to do so (n=6), I am curious how I set this question up to find out my chances of getting 'x' once out of the 6 times I try.

## Homework Equations

Binomial Distribution.

x! / y!(x - y)!

## The Attempt at a Solution

x = 0.2

y = 0.8

= 0.8! / 0.2! (0.8 - 0.2)!

= 40320 / 1440

= 28

Any help would be appreciated.