1. The problem statement, all variables and given/known data I am trying to figure out if I have a 20% chance to get what I want (let it = x) and I have 6 chances to do so (n=6), I am curious how I set this question up to find out my chances of getting 'x' once out of the 6 times I try. 2. Relevant equations Binomial Distribution. x! / y!(x - y)! 3. The attempt at a solution x = 0.2 y = 0.8 = 0.8! / 0.2! (0.8 - 0.2)! = 40320 / 1440 = 28 Any help would be appreciated.