- #1
kay123
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I'm trying to figure out this problem but i keep getting stuck.
Homework Statement
A woman wants to have a 95% chance for a least a one boy and at least one girl. What is the minimum number of children that she should plan to have? Assume that the event that a child is a girl and a boy is equiprobable and independent of the gender of the other children born in the family.
Relevant equations
So i know you should use Pr(K = k) = (n\choose k)p^k(1-p)^(n-k)
The attempt at a solution
since the it's a 95% chance Pr(K=k)= .95
probability of a boy or girl is 50% so it's .5
.95= (n\choose k).5^k(1-.5)^(n-k)
but then how would you solve or find what n and k is?
Am i missing something here?
Can anyone help! thank you in advance.
Homework Statement
A woman wants to have a 95% chance for a least a one boy and at least one girl. What is the minimum number of children that she should plan to have? Assume that the event that a child is a girl and a boy is equiprobable and independent of the gender of the other children born in the family.
Relevant equations
So i know you should use Pr(K = k) = (n\choose k)p^k(1-p)^(n-k)
The attempt at a solution
since the it's a 95% chance Pr(K=k)= .95
probability of a boy or girl is 50% so it's .5
.95= (n\choose k).5^k(1-.5)^(n-k)
but then how would you solve or find what n and k is?
Am i missing something here?
Can anyone help! thank you in advance.