Suppose you have a coin with 4 fair sides, flip it 5 times, and want to know the probability of 5 heads. This is(adsbygoogle = window.adsbygoogle || []).push({});

K(10,5) * (0.25)^{5}* (1-0.25)^{5}= K(10,5)*0.25^{5}*0.75^{5}

Or more generally for any binomially distributed outcome:

1) p(x=r) = p^{r}*(1-p)^{n-r}*K(n,r)

But also we must have that:

2) p(x=r) = K(n,r)/total combinations = K(n,r)/4^{n}

How do you show that 1) and 2) are equivalent?

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# Binomial distribution

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