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- Thread starter saadsarfraz
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vs.

nCk = n!/[(n-k)!k!]

Now (n+1)! = n!*(n+1) and (n+1-k)! = (n+1-k)(n-k)!

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HallsofIvy

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Pascal's triangle: (n+1)Ck= nC(j-1)+ nCj for k not 0.

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