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I am using the binomial formula (n choose k)p

^{k}(1-p)

^{n-k}where n = 10, p = 1/10, and k is the number of errors. Since the problem statement says less than 3 errors occur, I adding up the values for k = 0, 1, 2

(10 choose 0)(1/10)

^{0}(1-1/10)

^{10}+ (10 choose 1)(1/10)

^{1}(1-1/10)

^{9}+ (10 choose 2)(1/10)

^{2}(1-1/10)

^{8}, but i am wondering if I am doing this correctly? should i be adding or multiplying?