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Binomial Series Question

  • #1
1,235
1
How does one deduce the following:

We are given

[tex] \binom{-3}{n} = \frac{(-3)(-4)(-5)\cdot\cdot\cdot\cdot\cdot(-3-n+1)}{n!} = \frac{(-3)(-4)(-5)\cdot\cdot\cdot\cdot[-(n+2)]}{n!} [/tex]. How do we get from here to:



[tex] \frac{(-1)^{n}\cdot2\cdot3\cdot4\cdot5\cdot\cdot\cdot\cdot(n+1)(n+2)}{2\cdot n!} = \frac{(-1)^{n}(n+1)(n+2)}{2} [/tex]?


Thanks
 
Last edited:

Answers and Replies

  • #2
1,235
1
nevermind. I figured it out
 

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