A collision occurs between two football players. Player 1 has mass of 75 kg and a velocity of 6 m/s. Player 2 has mass of 150 kg and a velocity of -3 m/s (meaning going in an opposite direction). Assuming an ELASTIC collision, what is the final velocity of player 2?
They gave us this equation in class to calculate the final velocity:
m = mass
Vi = initial velocity
Vf = final velocity
a = player 1
b = player 2
Vfb = [(2*ma)/(ma+mb)]*Via + [(mb-ma)/(ma+mb)]*Vib
The Attempt at a Solution
Using the equation above and plugging in the numbers:
[(2*75kg)/(75kg + 150kg)]*(6 m/s)
[(150kg - 75kg)/(75kg + 150kg)]*(-3 m/s)
which gives me:
Vfb = 4 m/s + -1 m/s = 3 m/s
The "online" homework solution says it is -3 m/s. Am I incorrect? Did I miss a negative sign somewhere, or is there a principle of momentum that I am not getting?