A tendon starts off with an initial length of 10 cm and a cross-sectional area of 0.1 cm^2. A force of 100 N is applied, which stretches the ligament to a new length of 11 cm. What is the Modulus of Elasticity (E) for this ligament (in MPa)?
Stress = Force/Area
Strain = Change in Length/Original Length
E = Stress/Strain
The Attempt at a Solution
I tried this and my online homework solution tells me it is wrong. So I'll let you know what I did, and hopefully you guys can tell me if it looks right to you.
Stress = Force/Area = 100N/0.1cm^2 = 1000N/cm^2 (or if you want 10,000,000 N/m^2 same as 10,000,000 Pa)
Strain = Change in Length/Original Length = 1cm/10cm = 0.1
E = Stress/Strain = (10,000,000 Pa)/ 0.1 = 100,000,000 Pa or 100 MPa.
So my answer was 100 MPa. It says this is wrong...any ideas where I might have gone wrong, or is this correct? I am thinking of challenging it with the instructor because if you all think I got the right answer too, it might just be a mistake in the system.
Thanks for your help!!!