- #1

sillucius

- 6

- 0

**v**= [x, y, z] and there is also a dipole vector,

**p**, but those numbers are not important.

If under the given configuration, the lead vector is

**v**, what would the new lead vector,

**u**, be if the two leads were mixed up and reversed?

My guess is that the lead vector

**u**= -

**v**. This is because for a 2 lead system whose electrodes are i and j, the lead vector is

**c**ij =

**c**i -

**c**j.

Where

**c**represents the lead vector. If the leads are now switched, then the new lead vector would be:

**c**ji =

**c**j -

**c**i = -

**c**ij

Would this be the correct way to solve this question?