- #1
sillucius
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This is part 2 of a 2 part question. Suppose a measurement setup was given (It's just simply a setup with of a 2 lead system measuring a person's heart). The lead vector for this setup is given a v = [x, y, z] and there is also a dipole vector, p, but those numbers are not important.
If under the given configuration, the lead vector is v, what would the new lead vector, u, be if the two leads were mixed up and reversed?
My guess is that the lead vector u = -v. This is because for a 2 lead system whose electrodes are i and j, the lead vector is
cij = ci - cj.
Where c represents the lead vector. If the leads are now switched, then the new lead vector would be:
cji = cj - ci = -cij
Would this be the correct way to solve this question?
If under the given configuration, the lead vector is v, what would the new lead vector, u, be if the two leads were mixed up and reversed?
My guess is that the lead vector u = -v. This is because for a 2 lead system whose electrodes are i and j, the lead vector is
cij = ci - cj.
Where c represents the lead vector. If the leads are now switched, then the new lead vector would be:
cji = cj - ci = -cij
Would this be the correct way to solve this question?