Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Bipolar transistor breakdown

  1. May 8, 2006 #1
    Why is the breakdown voltage higher if the transistor is weakly doped? My intuition says that if the base and collector are weakly doped, the width of the depletion region will be bigger, so the number of extracted electrons/holes will increase, and so will the probability of ionisation by impact that leads to the avalanche multiplication, meaning that the breakdown voltage will be smaller. What is wrong in this?
     
  2. jcsd
  3. May 12, 2006 #2

    es

    User Avatar

    As you mentioned, a diode with higher doping levels has a larger built-in electric field therefore less external voltage is needed to achive the critical breakdown field. Thus the higher the doping the smaller the datasheet breakdown voltage is.
     
  4. May 12, 2006 #3

    es

    User Avatar

    oh ya, and vice versa
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Bipolar transistor breakdown
Loading...