0.5 kg bird lands on wire of telephone poles that are 50m apart. The wire sags 0.15m. What's the tension in the wire? Ignore weight of the wire
The Attempt at a Solution
I figured out the angle that would be created (0.34 degrees) when the bird lands and when I go to make individual equations for the x and y components of the tension I put Fy=2Tsin(0.34) - W +N=0. When I check the answer they do not include the normal force (N) in the equation. Why is that? Is it because we are ignoring the weight of the wire?