I'm having a little difficulty understanding a few key electronic concepts and am hoping a some of you may be able to shed light.(adsbygoogle = window.adsbygoogle || []).push({});

1) In a power source (i.e. battery) I understand that E = V / D. Despite the size and mass of an electron being incredibly small; when enter the field- do they accelerate (as they gain kinetic energy)? [This would make sense because work is being done on them.]

2) As they exit the battery, do they then travel at a constant velocity, assuming there is negligent resistance in circuit wires (i.e. obeying Newtons first Law of Inertia)?

The thing I'm finding most difficult to comprehend is what exactly happens in a voltage drop. My book states that, for series circuits, the current is constant but the voltage is divided proportionally to all resistance.

3) My understanding for the above is that the kinetic energy each electron possesses (in this case- its motion provided by a power source) is given by E = ½mv². As these electrons collide with atoms in a resistor they transfer some of their Kinetic Energy as Heat. Mathematically, this loss of Kinetic energy must mean their velocity is also be decreasing (in relation to the E = ½mv² formula); which contradicts the books statement that the current is constant throughout a series circuit.

Obviously there is a problem with my working somewhere... could someone please explain where I'm going wrong?

Much appreciated

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# Bit of trouble understanding basic electronics

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