- #1

erok81

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- 0

## Homework Statement

Write the volume element of d

^{3}p as a function of "nu". Assume spherical symmetry in doing this change of variables so write d

^{3}p = 4[tex]\pi[/tex]p

^{2}dp.

## Homework Equations

[tex]n(\nu)=\frac{1}{e^{\frac{h \nu}{kT}} -1}[/tex]

[tex]\epsilon=\frac{2}{h^3}\int h \nu \cdot n(\nu)d^3p[/tex]

## The Attempt at a Solution

I have zero idea of where to even start with this. As stupid as this is, I don't even understand "d

^{3}p = 4[tex]\pi[/tex]p

^{2}dp" or what the d

^{3}p even is. I don't think I've ever come across an integral that has used this type of notation before.

Any help to even get me started would be appreciated.