Black Hole Gaining Mass

1. Oct 22, 2009

ndoc

1. The problem statement, all variables and given/known data
If a black hole and a "normal" star orbit each other, gases from the normal star falling into the black hole can have their temperature increased by millions of degrees due to frictional heating. When the gases are heated that much, they begin to radiate light in the X-ray region of the electromagnetic spectrum (high-energy light photons). Cygnus X-1, the second strongest known X-ray source in the sky, is thought to be one such binary system; it radiates at an estimated power of 4.00x10^31 W. If we assume that 0.84 percent of the in-falling mass escapes as X ray energy, at what rate is the black hole gaining mass?

2. Relevant equations
E=m*c^2

3. The attempt at a solution
Wondering if someone could verify this because this question confuses me.

I'm assuming that the black hole absorbs 100-.84=99.16% of the power.

I take 4.00x10^31 * .9916 = 3.9664x10^31 J

Using E=m*c^2 => m = 3.9664x10^31/((3x10^8)^2) = 4.407x10^4 kg/s

Does this seem a logical conclusion, am I interpreting the question correctly? Thanks in advance.

2. Oct 22, 2009

willem2

That's not right. The 4.00x10^31 W isn't the total power but only 0.84% of it. The other 99.16% goes into the hole.

3. Oct 22, 2009

ndoc

Right, which is why I take 4x10^31*.9916 to get the J absorbed by the black hole per second. Am I right in doing so, or am I doing something wrong?

4. Oct 22, 2009

ndoc

Ok I see now,

Total*.0084 = 4x10^31

Mass entering per second = 4x10^31*.9916/.0084 = 4.72x10^33

4.72x10^33 / ((3x10^8)^2) = 5.247x10^16 kg/s is the right answer, thanks for the help!