Blackbody radiation problem!! 1. The problem statement, all variables and given/known data The average person has 1.4 m^2 of skin at a skin temperature of roughly 306 K. Consider the average person to be an ideal radiator standing in a room at a temperature of 293 K. a.) Calculate the energy per second radiated by the average person in the form of blackbody radiation. Express you answer in watts. (How do I treat the temperature?) 2. Relevant equations L=AσT^4 Where A = area; σ = Stefan-Boltzmann constant; T = temperature (in Kelvins). 3. The attempt at a solution L=(1.4)*(5.670400*10^-8)*(????)^4
Re: Blackbody radiation problem!! The energy per second radiated will just be that equation with body temperature as T (~310 Kelvin); but note that this isn't the same as the total energy lost per second.
Re: Blackbody radiation problem!! Energy radiated per unit time will be given by Stefan-Boltzman law - dQ/dt = eAσT^4 (σ - Stefan's constant) but here 'T' is to be taken in Kelvin and not degree celsius. and also this is not the energy lost since energy lost = (Energy radiated)-(Energy absorbed) put T value in the equation. For heat radiated T=306 and for absorbed T=293