- #1

Sylis

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I'm working on the problem above, and through Google found this link. I understand how to accomplish the problem. However, I'm having trouble identifying the forces in play. My teacher wants us to accomplish these sort of problems a very specific sort of way.

1) Identify forces (In this case I'd have horizontal forces and vertical forces)

2)Draw a free-body diagram

3) Apply Newton's second law in Component form. (ƩF

_{x}=ma

_{x}/ƩF

_{y}=ma

_{y})

And solve.

So far my horizontal force is the Push force (30cos12) and my vertical forces are Static Friction, weight and also Push force (30sin12).

"Fnet(x) = Fn - Fpush(x) , and since Fnet(x) is 0, then Fn = Fpush (x)" (from link)

I'm not understanding where he is getting Fn from or what Fn even stands for, I thought perhaps it was normal force, but there is no horizontal surface the block of wood is on, so there should be no normal force.