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https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2111/fall/homework/Ch-12-Equilibrium/block-strut/block-strut-eq.gif [/URL]
Sorry, forgot to add the picture...
1. Homework Statement
The system shown to the right is in equilibrium. The steel block has a mass m1 = 248 kg and the uniform rigid aluminum strut has a mass m2 = 47 kg. The strut is hinged so that it can pivot freely about it's bottom end. The angle between the left wire and the ground is Θ = 32o and the angle between the strut and the ground is φ = 49o
torque = rFsin(theta)
a) What is the tension in the vertical wire that holds the steel block? 2432.88 N
b) What is the tension in the left angled wire?
torque(hinge) = 0 = m(block)Lcos(49) + 0.5(m(strut)Lcos(49) - T2Lcos(49-32)
I got T2 = 1827.197
That seems low for where the pivot is.
Any idea were I screwed up? Thanks!
Sorry, forgot to add the picture...
1. Homework Statement
The system shown to the right is in equilibrium. The steel block has a mass m1 = 248 kg and the uniform rigid aluminum strut has a mass m2 = 47 kg. The strut is hinged so that it can pivot freely about it's bottom end. The angle between the left wire and the ground is Θ = 32o and the angle between the strut and the ground is φ = 49o
Homework Equations
torque = rFsin(theta)
The Attempt at a Solution
a) What is the tension in the vertical wire that holds the steel block? 2432.88 N
b) What is the tension in the left angled wire?
torque(hinge) = 0 = m(block)Lcos(49) + 0.5(m(strut)Lcos(49) - T2Lcos(49-32)
I got T2 = 1827.197
That seems low for where the pivot is.
Any idea were I screwed up? Thanks!
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