A 198g wood block is firmly attached to a very light horizontal spring, as shown in the figure below.(adsbygoogle = window.adsbygoogle || []).push({});

The block can slide along a table where the coefficient of friction is 0.287. A force of 23.1 N compresses the spring 17.7 cm. If the spring is released from this position, how far beyond its equilibrium position will it stretch on its first swing

the way i approached this:

1/2kx^2 - Ukmgx = 1/2mv^2 = UkmgD

where D is the distance it travels after acquiring kinetic energy.

however, there is something wrong with this approach and i cannot figure out what it is. please help!

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# Homework Help: Block can slide along a table where the coefficient of friction

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